-- =============================================================================
-- 人员管理(yz_backend_employee) 与 用户管理(yz_system_tenant_user) 老数据对齐
--
-- 背景：员工表早期建的是「账号全局唯一」索引 uk_account(account)，多租户后同一账号
-- 在不同企业只能存在一份员工档案；再叠加历史手工录入的人员（如 hero001 这类旧账号），
-- 导致「OA 设置 → 人员管理」与「基本设置 → 用户管理」两边数据对不上。
--
-- 处理内容：
--   1. 索引调整为 (tid, account) 唯一  ← 必须最先执行，否则第 3 步会撞全局唯一键
--   2. 员工 tid 为空/0：按唯一账号补 tid
--   3. 同一企业内「用户缺员工 + 存在同名无账号老员工」：把老员工账号改成用户账号
--      （保留员工 ID，排班 / 日报 / 人事档案的历史引用不受影响）
--   4. 用户仍然没有员工：按用户资料补建员工记录（与「用户管理 → 同步员工」同规则）
--   5. 复核查询 + 仍需人工确认的清单
--
-- 反向缺口（「人员管理有、用户管理没有」）不在这里处理：补账号要先在统一认证建身份
-- 并生成 argon2id 密码哈希，SQL 做不到，用 Go 工具：
--   go run scripts/syncemployeeusers/main.go -tid <企业ID> -apply
--
-- 特性：可重复执行（幂等），第 2 次执行不会产生任何变更。
-- 执行前请务必备份：mysqldump -u root -p go-platform > backup_$(date +%F).sql
-- 执行后请重启 backend 服务：services/employee_sync.go 已改为按 (tid, account) 匹配员工。
-- =============================================================================

-- -----------------------------------------------------------------------------
-- 0. 执行前预检（只看不改）
-- -----------------------------------------------------------------------------
SELECT '执行前：用户/员工数量' AS section;
SELECT
  (SELECT COUNT(*) FROM yz_system_tenant_user WHERE delete_time IS NULL) AS user_rows,
  (SELECT COUNT(*) FROM yz_backend_employee WHERE delete_time IS NULL) AS employee_rows,
  (SELECT COUNT(*) FROM yz_backend_employee WHERE delete_time IS NULL AND (tid IS NULL OR tid = 0)) AS employee_tid_empty,
  (SELECT COUNT(*) FROM yz_system_tenant_user u
     WHERE u.delete_time IS NULL AND u.account IS NOT NULL AND TRIM(u.account) <> ''
       AND NOT EXISTS (SELECT 1 FROM yz_backend_employee e
                       WHERE e.delete_time IS NULL AND e.tid = u.tid AND TRIM(e.account) = TRIM(u.account))
  ) AS user_without_employee;

-- 若下面这条 > 0，需要先人工处理重复的 (tid, account)，否则第 1 步加唯一索引会失败
SELECT '重复的 (tid, account)' AS section;
SELECT tid, TRIM(account) AS account, COUNT(*) AS cnt
FROM yz_backend_employee
WHERE delete_time IS NULL
GROUP BY tid, TRIM(account)
HAVING COUNT(*) > 1;

-- -----------------------------------------------------------------------------
-- 1. 索引：账号全局唯一 → 企业内唯一
--    关键：不先放开全局唯一，第 3 步把 hero001 改成 hero920103 会因另一企业已占用而失败
-- -----------------------------------------------------------------------------
SET @has_old := (SELECT COUNT(*) FROM information_schema.STATISTICS
                 WHERE TABLE_SCHEMA = DATABASE() AND TABLE_NAME = 'yz_backend_employee'
                   AND INDEX_NAME = 'uk_account');
SET @sql := IF(@has_old > 0, 'ALTER TABLE yz_backend_employee DROP INDEX uk_account', 'DO 0');
PREPARE stmt FROM @sql; EXECUTE stmt; DEALLOCATE PREPARE stmt;

SET @has_plain := (SELECT COUNT(*) FROM information_schema.STATISTICS
                   WHERE TABLE_SCHEMA = DATABASE() AND TABLE_NAME = 'yz_backend_employee'
                     AND INDEX_NAME = 'idx_tid_account');
SET @sql := IF(@has_plain > 0, 'ALTER TABLE yz_backend_employee DROP INDEX idx_tid_account', 'DO 0');
PREPARE stmt FROM @sql; EXECUTE stmt; DEALLOCATE PREPARE stmt;

SET @has_uk := (SELECT COUNT(*) FROM information_schema.STATISTICS
                WHERE TABLE_SCHEMA = DATABASE() AND TABLE_NAME = 'yz_backend_employee'
                  AND INDEX_NAME = 'uk_tid_account' AND NON_UNIQUE = 0);
SET @sql := IF(@has_uk = 0,
               'ALTER TABLE yz_backend_employee ADD UNIQUE KEY uk_tid_account (tid, account)',
               'DO 0');
PREPARE stmt FROM @sql; EXECUTE stmt; DEALLOCATE PREPARE stmt;

-- -----------------------------------------------------------------------------
-- 2. 员工 tid 为空/0：按账号唯一匹配到企业用户后补 tid
-- -----------------------------------------------------------------------------
UPDATE yz_backend_employee e
JOIN (
  SELECT TRIM(account) AS account, MIN(tid) AS tid
  FROM yz_system_tenant_user
  WHERE delete_time IS NULL AND account IS NOT NULL AND TRIM(account) <> ''
  GROUP BY TRIM(account)
  HAVING COUNT(DISTINCT tid) = 1
) u ON u.account = TRIM(e.account)
SET e.tid = u.tid,
    e.update_time = NOW()
WHERE e.delete_time IS NULL
  AND (e.tid IS NULL OR e.tid = 0);

-- -----------------------------------------------------------------------------
-- 3. 同企业内同名老员工账号对齐
--    条件：① 员工账号在本企业没有对应用户（历史手工人员）
--          ② 该用户在本企业还没有员工
--          ③ 按姓名能唯一匹配到一个用户
--    只改 account，不动 id，历史引用全部保留
-- -----------------------------------------------------------------------------
DROP TEMPORARY TABLE IF EXISTS tmp_emp_align;
CREATE TEMPORARY TABLE tmp_emp_align (
  emp_id      BIGINT UNSIGNED NOT NULL PRIMARY KEY,
  tid         BIGINT          NOT NULL,
  old_account VARCHAR(64)     NOT NULL,
  new_account VARCHAR(64)     NOT NULL
) ENGINE = InnoDB;

INSERT INTO tmp_emp_align (emp_id, tid, old_account, new_account)
SELECT e.id, e.tid, TRIM(e.account), MIN(TRIM(u.account))
FROM yz_backend_employee e
JOIN yz_system_tenant_user u
  ON u.tid = e.tid
 AND u.delete_time IS NULL
 AND u.account IS NOT NULL
 AND TRIM(u.account) <> ''
 AND TRIM(u.name) = TRIM(e.name)
LEFT JOIN yz_system_tenant_user ux
  ON ux.tid = e.tid
 AND ux.delete_time IS NULL
 AND TRIM(ux.account) = TRIM(e.account)
LEFT JOIN yz_backend_employee ex
  ON ex.tid = e.tid
 AND ex.delete_time IS NULL
 AND TRIM(ex.account) = TRIM(u.account)
WHERE e.delete_time IS NULL
  AND e.tid IS NOT NULL
  AND e.tid > 0
  AND ux.id IS NULL          -- 员工账号在本企业没有用户
  AND ex.id IS NULL          -- 用户在本企业还没有员工
GROUP BY e.id, e.tid, TRIM(e.account)
HAVING COUNT(DISTINCT TRIM(u.account)) = 1;   -- 同名用户不唯一时不动，留待人工

UPDATE yz_backend_employee e
JOIN tmp_emp_align t ON t.emp_id = e.id
SET e.account = t.new_account,
    e.update_time = NOW();

SELECT '第 3 步：对齐的老员工账号' AS section, emp_id, tid, old_account, new_account
FROM tmp_emp_align;

DROP TEMPORARY TABLE IF EXISTS tmp_emp_align;

-- -----------------------------------------------------------------------------
-- 4. 用户仍然没有员工：按用户资料补建员工记录
--    与 services/EnsureEmployeeForTenantUser 的规则一致（账号、姓名、性别、生日、
--    部门、手机、邮箱、启用状态），密码留空（登录走统一认证，不校验员工密码）
-- -----------------------------------------------------------------------------
INSERT INTO yz_backend_employee
  (tid, account, password, name, gender, birthday, department, phone, email,
   account_status, create_time, update_time)
SELECT
  u.tid,
  TRIM(u.account),
  '',
  COALESCE(NULLIF(TRIM(u.name), ''), TRIM(u.account)),
  IFNULL(u.sex, 0),
  STR_TO_DATE(LEFT(TRIM(IFNULL(u.birth, '')), 10), '%Y-%m-%d'),
  CASE WHEN IFNULL(u.org_id, 0) > 0 THEN CAST(u.org_id AS CHAR) ELSE NULL END,
  NULLIF(TRIM(IFNULL(u.phone, '')), ''),
  NULLIF(TRIM(IFNULL(u.email, '')), ''),
  IF(IFNULL(u.status, 1) = 0, 0, 1),
  NOW(), NOW()
FROM yz_system_tenant_user u
LEFT JOIN yz_backend_employee e
  ON e.delete_time IS NULL
 AND e.tid = u.tid
 AND TRIM(e.account) = TRIM(u.account)
WHERE u.delete_time IS NULL
  AND u.account IS NOT NULL
  AND TRIM(u.account) <> ''
  AND e.id IS NULL;

-- -----------------------------------------------------------------------------
-- 5. 复核
-- -----------------------------------------------------------------------------
SELECT '执行后：用户/员工数量' AS section;
SELECT
  (SELECT COUNT(*) FROM yz_system_tenant_user WHERE delete_time IS NULL) AS user_rows,
  (SELECT COUNT(*) FROM yz_backend_employee WHERE delete_time IS NULL) AS employee_rows,
  (SELECT COUNT(*) FROM yz_backend_employee WHERE delete_time IS NULL AND (tid IS NULL OR tid = 0)) AS employee_tid_empty,
  (SELECT COUNT(*) FROM yz_system_tenant_user u
     WHERE u.delete_time IS NULL AND u.account IS NOT NULL AND TRIM(u.account) <> ''
       AND NOT EXISTS (SELECT 1 FROM yz_backend_employee e
                       WHERE e.delete_time IS NULL AND e.tid = u.tid AND TRIM(e.account) = TRIM(u.account))
  ) AS user_without_employee;

-- 按企业对比：用户数 / 员工数 / 本企业无账号的员工数
SELECT
  u.tid,
  u.user_cnt,
  e.emp_cnt,
  e.emp_without_user
FROM (
  SELECT tid, COUNT(*) AS user_cnt
  FROM yz_system_tenant_user
  WHERE delete_time IS NULL
  GROUP BY tid
) u
LEFT JOIN (
  SELECT x.tid,
         COUNT(*) AS emp_cnt,
         SUM(CASE WHEN ux.id IS NULL THEN 1 ELSE 0 END) AS emp_without_user
  FROM yz_backend_employee x
  LEFT JOIN yz_system_tenant_user ux
    ON ux.tid = x.tid
   AND ux.delete_time IS NULL
   AND TRIM(ux.account) = TRIM(x.account)
  WHERE x.delete_time IS NULL
  GROUP BY x.tid
) e ON e.tid = u.tid
ORDER BY u.tid;

-- -----------------------------------------------------------------------------
-- 6. 仍需人工确认：员工在本企业没有登录账号（老数据，脚本不删除也不改）
--    处理方式二选一：
--      a) 在「用户管理」用相同账号添加用户 → 会自动关联到已有员工档案，不会重复建档
--      b) 在「人员管理」把这些人员设为离职（account_status = 2）
-- -----------------------------------------------------------------------------
SELECT '仍无登录账号的员工' AS section,
       e.tid, e.id, TRIM(e.account) AS account, TRIM(e.name) AS name,
       TRIM(IFNULL(e.department, '')) AS department
FROM yz_backend_employee e
LEFT JOIN yz_system_tenant_user u
  ON u.tid = e.tid
 AND u.delete_time IS NULL
 AND TRIM(u.account) = TRIM(e.account)
WHERE e.delete_time IS NULL
  AND u.id IS NULL
ORDER BY e.tid, e.id;